0=0.24x^2-3.8x+12.5

Solution for 0=0.24x^2-3.8x+12.5 equation:

0=0.24x^2-3.8x+12.5

We move all terms to the left:

0-(0.24x^2-3.8x+12.5)=0

We add all the numbers together, and all the variables

-(0.24x^2-3.8x+12.5)=0

We get rid of parentheses

-0.24x^2+3.8x-12.5=0

a = -0.24; b = 3.8; c = -12.5;
Δ = b2-4ac
Δ = 3.82-4·(-0.24)·(-12.5)
Δ = 2.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.8)-\sqrt{2.44}}{2*-0.24}=\frac{-3.8-\sqrt{2.44}}{-0.48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.8)+\sqrt{2.44}}{2*-0.24}=\frac{-3.8+\sqrt{2.44}}{-0.48}
$